Question
Factorise:
9a2 + 3a - 8b - 64b2
9a2 + 3a - 8b - 64b2
✓
Answer
9a2 + 3a - 8b - 64b2
= 9a2 - 64b2 + 3a - 8b
= (3a)2 - (8b)2 + (3a - 8b) $\big[\therefore\ \text{a}^2-\text{b}^2=(\text{a}-\text{b})(\text{a}+\text{b})\big]$
= (3a + 8b)(3a - 8b) + (3a - 8b)
= (3a - 8b)(3a + 8b + 1)
= 9a2 - 64b2 + 3a - 8b
= (3a)2 - (8b)2 + (3a - 8b) $\big[\therefore\ \text{a}^2-\text{b}^2=(\text{a}-\text{b})(\text{a}+\text{b})\big]$
= (3a + 8b)(3a - 8b) + (3a - 8b)
= (3a - 8b)(3a + 8b + 1)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Look at the bar graph given below.
Expand:
(3x + 2)3
(3x + 2)3
Read the Source/ Text given below and answer the questions:
Veena planned to make a jewellery box to gift her friend Reeta on her marriage. She made the jewellery box of wood in the shape of a cuboid. The jewellery box has the dimensions as shown in the figure below. The rate of painting the exterior of the box is Rs. 2 per cm2. After making the box she took help from his friends to decorate the box. The blue colour was painted by Deepak, Black by Suresh, green by Harsh and the yellow was painted by Naresh.
1. What is the volume of the box?
2. How much area did Suresh paint?
Veena planned to make a jewellery box to gift her friend Reeta on her marriage. She made the jewellery box of wood in the shape of a cuboid. The jewellery box has the dimensions as shown in the figure below. The rate of painting the exterior of the box is Rs. 2 per cm2. After making the box she took help from his friends to decorate the box. The blue colour was painted by Deepak, Black by Suresh, green by Harsh and the yellow was painted by Naresh.
1. What is the volume of the box?
2. How much area did Suresh paint?
Simplify the following expression:
→$(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2})$
In figure, rays AB and CD intersect at O.
Determine x when y = 40°.
Determine x when y = 40°.
Express the following rational numbers as decimals:
$-\frac{4}{9}$
→$-\frac{4}{9}$
Factorise y2 – 5y + 6 by using the Factor Theorem.
Write the equation of a line Passing through the point (0, 4) and parallel to x-axis.
Factorise:
7a3 + 56b3
7a3 + 56b3
Factorise:
64a3 - 343
64a3 - 343