Question
Factorise:
a3 + 0.008

Answer

a3 + 0.008
= (a)3 + (0.2)3
= (a + 0.2)[(a)2 - a × 0.2 + (0.2)2] Since a3 + b3 = (a + b)(a2 - a × b + b2)
= (a + 0.2)(a2 - 0.2a + 0.04)

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