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Factorisation — MATHS STD 8 — Question

ICSE BoardEnglish MediumSTD 8MATHSFactorisation3 Marks
Question
Factorise: $\left(7 \frac{3}{10}\right)^2-\left(2 \frac{1}{10}\right)^2$
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Answer

$ \left(7 \frac{3}{10}\right)^2-\left(2 \frac{1}{10}\right)^2$
$ =\left(\frac{73}{10}\right)^2-\left(\frac{21}{10}\right)^2$
$ =\left(\frac{73}{10}+\frac{21}{10}\right)\left(\frac{73}{10}-\frac{21}{10}\right) \ldots\left[\mathrm{a}^2-\mathrm{b}^2=(\mathrm{a}+\mathrm{b})(\mathrm{a}-\mathrm{b})\right]$
$ =\left(\frac{94}{10}\right)\left(\frac{52}{10}\right)$
$ =\left(\frac{47}{5}\right)\left(\frac{26}{5}\right)=\frac{1222}{25}=48 \frac{22}{25}$

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