ICSE BoardEnglish MediumSTD 9MATHEMATICSFactorisation3 Marks
Question
Factorise the following by taking out the common factors:$2a(p^2 + q^2) + 4b(p^2 + q^2)$
✓
Answer
$2 a\left(p^2+q^2\right)+4 b\left(p^2+q^2\right)$
Here, the common factor is $2\left(p^2+q^2\right)$
Dividing throughtout by $2\left(p^2+q^2\right)$,
we get
$\frac{2 a\left(p^2+q^2\right)}{2\left(p^2+q^2\right)}+\frac{4 b\left(p^2+q^2\right)}{2\left(p^2+q^2\right)} $
$=a+2 b $
$\therefore 2 a\left(p^2+q^2\right)+4 b\left(p^2+q^2\right) $
$=2\left(p^2+q^2\right)(a+2 b) .$
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