Question
Factorise the following by the difference of two squares$:(x - 2y)^2 -z^2$
✓
Answer
$(x - 2y)^2 - z^2$
$= (x - 2y)^2 - (z)^2$
$= (x - 2y - z)(x - 2y + z).$
$= (x - 2y)^2 - (z)^2$
$= (x - 2y - z)(x - 2y + z).$
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