Question
Factorise the following:$2 x^2+\frac{x}{6}-1$
✓
Answer
$2 x^2+\frac{x}{6}-1$
$=\frac{1}{6}\left(12 x^2+x-6\right) $
$=\frac{1}{6}\left(12 x^2+9 x-8 x-6\right) $
$=\frac{1}{6}[3 x(4 x+3)-2(4 x+3)] $
$=\frac{1}{6}[(4 x+3)(3 x-2)]$
$ =\frac{1}{6}(4 x+3)(3 x-2) .$
$=\frac{1}{6}\left(12 x^2+x-6\right) $
$=\frac{1}{6}\left(12 x^2+9 x-8 x-6\right) $
$=\frac{1}{6}[3 x(4 x+3)-2(4 x+3)] $
$=\frac{1}{6}[(4 x+3)(3 x-2)]$
$ =\frac{1}{6}(4 x+3)(3 x-2) .$
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