Question
Factorize of the following expressions:
$Lm^2- mn^2- Lm + n^2$
$Lm^2- mn^2- Lm + n^2$
✓
Answer
$ L m^2-m n^2-L m+n^2=\left(L m^2-L m\right)+\left(n^2-m n^2\right) $
$ ={Lm}(m-1)+n^2(1-m) $
$ ={Lm}(m-1)-n^2(m-1)[\text { since, }(1-m) $
$= -(m - 1)] = (Lm - n^2)(m - 1) [$taking $(m -1)$ as the common factor$]$
$ ={Lm}(m-1)+n^2(1-m) $
$ ={Lm}(m-1)-n^2(m-1)[\text { since, }(1-m) $
$= -(m - 1)] = (Lm - n^2)(m - 1) [$taking $(m -1)$ as the common factor$]$
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