Question
Factorize the following expressions:
p3 + 27
p3 + 27
✓
Answer
p3 + 27
= p3 + 33
$\therefore$ [a3 + b3 = (a + b)(a2 - ab + b2)]
= (p + 3)(p² - 3p - 9)
$\therefore$ p3 + 27 = (p + 3)(p² - 3p - 9)
= p3 + 33
$\therefore$ [a3 + b3 = (a + b)(a2 - ab + b2)]
= (p + 3)(p² - 3p - 9)
$\therefore$ p3 + 27 = (p + 3)(p² - 3p - 9)
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