MCQ
Ferrous sulphate on heating gives
- A$SO_2$ and $SO_3$
- B$SO_2$ only
- ✓$SO_3$ only
- D$H_2S$ only
✓
Answer
Correct option: C.
$SO_3$ only
c
${S^{2 - }}\, + \,{(C{H_3}COO)_2}Pb\, \to \,\mathop {PbS}\limits_{black} \downarrow \, + \,2C{H_3}CO{O^ - }$
${S^{2 - }}\, + \,{(C{H_3}COO)_2}Pb\, \to \,\mathop {PbS}\limits_{black} \downarrow \, + \,2C{H_3}CO{O^ - }$
${S^{2 - }}\, + \,{[Fe{(CN)_5}NO]^{2 - }}\, \to \,\mathop {{{[Fe{{(CN)}_5}NOS]}^{4 - }}}\limits_{violet} $
Thus $S^{2-}$ and $SO_3^{2-}$ can be distinguished by using both the given reagents.
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