Question
Figure shows a closed surface which intersects a conducting sphere. If a positive charged is placed at the point P, the flux of the electic field through the closed surface:
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Answer
- Will become positive.
Charge distribution:
Due to charge distribution, intersection by the closed surface of conducting sphere containing the positive charge. So we can say that the flux of the electric field through the closed surface will become positive.
$\therefore\phi=\frac{\text{q}_{\text{in}}}{\epsilon_0}\Rightarrow+\text{ve}$
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