Question
Figure shows a heavy block kept on a frictionless surface and being pulled by two ropes of equal mass m. At t = 0, the force on the left rope is withdrawn but the
force on the right end continues to act. Let F1 and F2 be the magnitudes of the forces by the right rope and the left rope on the block respectively:

  1. F= F2 = F for t < 0.
  2. F1 = F2 = F + mg for t < 0.
  3. F1 = F, F2 = F for t > 0.
  4. F1< F, F2 = F for t > 0.

Answer

  1. F= F2 = F for t < 0.

Explanation:

At t < 0, the block is in equilibrium in the horizontal direction.

So, F1 = F2 = F

At t > 0, F2 = 0 and F1 = F.

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