Find a number whose double is 45 greater than its half. - Vidyadip

Question

Find a number whose double is 45 greater than its half.

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Answer

Let the requierd number = x Then Four-fifth of the number = 2x And half of it $=\frac{\text{x}}{2}$ $\therefore$ According to the condition:$2\text{x}-\frac{\text{x}}{2}=45$
$\Rightarrow\frac{4\text{x}-\text{x}}{2}=45$
$\Rightarrow\frac{3}{2}\text{x}=45$
$\Rightarrow\text{x}=\frac{45\times2}{3}=30$
$\therefore$ Required number = 30 Check: $2\times30-\frac{1}{2}\times30$ = 6 - 15 = 45, which is given $\therefore$ Our answer is correct.

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