MCQ
Find $B$
- A
- B
- C
- ✓
✓
Answer
Correct option: D.
d
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$\begin{matrix}
OH\,\, \\
|\,\,\,\,\,\,\, \\
C{{H}_{3}}-CH-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\, \\
||\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\to \\
\end{matrix}\begin{matrix}
OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-CH-{{(C{{H}_{2}})}_{3}}-C{{H}_{3}} \\
\end{matrix}$
→OH\,\, \\
|\,\,\,\,\,\,\, \\
C{{H}_{3}}-CH-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\, \\
||\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\to \\
\end{matrix}\begin{matrix}
OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-CH-{{(C{{H}_{2}})}_{3}}-C{{H}_{3}} \\
\end{matrix}$
Above conversion can be achieved by
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