Question
Find $\frac{d y}{d x}$ if
$x^2 y^2-\tan ^{-1}\left(\sqrt{x^2+y^2}\right)=\cot ^{-1}\left(\sqrt{x^2+y^2}\right)$
$x^2 y^2-\tan ^{-1}\left(\sqrt{x^2+y^2}\right)=\cot ^{-1}\left(\sqrt{x^2+y^2}\right)$
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