Question
Find if the following number is a perfect cube? $1728$

Answer

$1728$
$2$ $1728$
$2$ $864$
$2$ $432$
$2$ $216$
$2$ $108$
$2$ $54$
$3$ $27$
$3$ $9$
$3$ $3$
  $1$
$\because 1728 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3$
$= (2)^3 \times (2)^3 \times (3)^3$
$\because 1728$ is a perfect cube.

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