MCQ
Find incorrect comparison of second ionisation energy
- ✓$Te < Sb$
- B$In > Sr$
- C$He > B$
- D$Fe < Fe^+$
It is not easy to remove electron from half filled $P$ orbital.
Hence second ionisation energy of $T e$ is greater than $Sb$.
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when $\underset{(i)}{\mathop{\gamma =C{{H}_{3}}CO_{2}^{-},}}\,\,\,\,\,\,\underset{(ii)}{\mathop{Cl-C{{H}_{2}}-CO_{2}^{-},}}\,\,\,\,\,\,\,\underset{(iii)}{\mathop{Ph-SO_{3}^{-}}}\,$
Which of the following compounds can be $A$ ?