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DIFFERENTIATION — Statistics STD 12 Commerce — Question

Gujarat BoardEnglish MediumSTD 12 CommerceStatisticsDIFFERENTIATION1 Mark
Question
Find $\frac{\mathbf{d y}}{\mathbf{d x}}$ if $y=x^3+x^2+x-2$
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Answer

Here, $y=x^3+x^2+x-2$
$\therefore \frac{d y}{d x} =\frac{d}{d x}\left( x ^3+ x ^2+ x -2\right)$
$=\frac{d}{d x}\left( x ^3\right)+\frac{d}{d x}\left( x ^2\right)+\frac{d}{d x}( x )-\frac{d}{d x}$
$=3 x^2+2 x+1-0$
$=3 x^2+2 x+1$
$(2)$
$\therefore \frac{d y}{d x}=3 x^2+2 x+11$

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