MCQ
find out the reactivity order with $LiAlH_4$


- A$A > B > C > D$
- ✓$B > C > D > A$
- C$D > C > B > A$
- D$B > D > C > A$

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$A\xrightarrow[{(ii)\,\,Conc.\,{H_2}S{O_4}/\Delta }]{{{\text{(i)}}\,{\text{C}}{{\text{H}}_3}MgBr/{H_2}O}}$
$B\xrightarrow[{(ii)\,Zn/{H_2}O}]{{(i)\,{O_3}}}C + D$
$D\xrightarrow[\Delta ]{{Ba\left( {OH} \right)}}\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {{H_3}C - C} \end{array}$$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,||} \\ { = CH - C - C{H_3}} \end{array}$
$R-Cl\xrightarrow{(i)\,\,KCN,(ii)\,LiAl{{H}_{4}}} $ Product $A$
$R-Cl\xrightarrow{(i)\,\,AgCN,(ii)\,LiAl{{H}_{4}}} $ Product $B $
the compounds $A$ and $B$ are
