Question
Find the altitude of a triangle whose area is $42 cm^2$ and base is 12 cm .
✓
Answer
We have,
Attitude of a triangle $=\frac{2 \times \text { Area }}{\text { Base }}$
Here, base $=12 cm^{-2}$ and area $=42 cm^2$
Attitude $=\frac{2 \times 42}{12}=7 cm$
Attitude of a triangle $=\frac{2 \times \text { Area }}{\text { Base }}$
Here, base $=12 cm^{-2}$ and area $=42 cm^2$
Attitude $=\frac{2 \times 42}{12}=7 cm$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the diameter of a circle whose circumference is:
12.56cm
12.56cm
In Figure, AOC is a line, find x.
Add $2 x^2-3 x+1$ to the sum of $3 x^2-2 x$ and $3 x+7$.
→Find:$\frac{5}{6}\text{ of a day}$
→Simplify:
(-16) × (- 8) + (- 4) × (-8)
(-16) × (- 8) + (- 4) × (-8)
Show that 36, 49, 6, 7 are not in proportion.
Find the median of:
21, 15, 6, 25, 18, 13, 20, 9, 16, 8, 22
21, 15, 6, 25, 18, 13, 20, 9, 16, 8, 22
Find the HCF and LCM.32,16
State which is greater:
{(-2) - 5} × (-6) and (-2) - 5 × (-6)
{(-2) - 5} × (-6) and (-2) - 5 × (-6)
Observe the figure and answer the following questions.T is a point on line AB.
- What kind of angle is ∠ATB ?
- What is its measure ?