Question
Find the angle of projection for a projectile motion whose range R is n times the maximum height H.

Answer

Given R = nH $\Rightarrow\ \frac{\text{u}^2\sin2\theta}{\text{g}}=\text{n}\times\frac{\text{u}^2\sin^2\theta}{2\text{g}}$ $\Rightarrow\ \theta=\tan^{-1}\Big(\frac{4}{\text{n}}\Big)$

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