Question
Find the area of a square whose diagonal is $5\sqrt{2}\text{cm}.$ Hint: Area $=\Big[\frac{1}{2}\times (\text{diagonal})^2\Big]\text{sq}-\text{units}.$

Answer

Area of the square $=\Big\{\frac{1}{2}\times(\text{Diagonal})^2\Big\}\text{sq}-\text{units}$
$=\Big\{\frac{1}{2}\times (5\sqrt{2})^2\Big\}\text{cm}^2$
$=\Big\{\frac{1}{2}\times (5)^2\times (\sqrt{2})^2\Big\}\text{cm}^2$
$=\Big\{\frac{1}{2}\times25\times2\Big\}\text{cm}^2$
$=\Big(\frac{1}{2}\times 50\Big)\text{cm}^2$
$=25\text{cm}^2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free