Question
Find the cube of: $1 \frac{2}{7}$
✓
Answer
$ 1 \frac{2}{7}$
$ =\left(1 \frac{2}{7}\right)^3$
$ =\left(\frac{1 \times 7+2}{7}\right)^3$
$ =\left(\frac{9}{7}\right)^3$
$ =\frac{9 \times 9 \times 9}{7 \times 7 \times 7}$
$=\frac{729}{343}$
$=2 \frac{43}{343}$
$ =\left(1 \frac{2}{7}\right)^3$
$ =\left(\frac{1 \times 7+2}{7}\right)^3$
$ =\left(\frac{9}{7}\right)^3$
$ =\frac{9 \times 9 \times 9}{7 \times 7 \times 7}$
$=\frac{729}{343}$
$=2 \frac{43}{343}$
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