Find the cube-root of -27 125 - Vidyadip

Question

Find the cube$-$root of $-\frac{27}{125}$

✓

Answer

$ -\frac{27}{125}$
$ =-\frac{\sqrt{27}}{\sqrt{125}}$
$ =-\sqrt{\frac{3 \times 3 \times 3}{5 \times 5 \times 5}}$
$ =-\frac{3}{5}$

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