Question
Find the cubes of the following number by column method:
$72$
$72$
|
Column I
|
Column II
|
Column III
|
Column IV
|
| $a ^3$ | $3 \times a ^2 \times b$ | $3 \times a \times b ^2$ | $B^3$ |
| $7^3=343$ | $3 \times a ^2 \times b =3 \times 7^2 \times 2=294$ | $3 \times a \times b ^2=3 \times 7 \times 2^2=84$ | $2^3=8$ |
|
+30
|
+8
|
+0
|
8
|
|
373
|
302
|
84
|
|
|
373
|
2
|
4
|
8
|
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