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Limits and Derivatives — MATHS STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceMATHSLimits and Derivatives2 Marks
Question
Find the derivative of function 3 cot x + 5 cosec x
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Answer

Here f (x) = 3 cot x + 5 cosec x
$\therefore \;{\text{f'}}(x) = \frac{d}{{dx}}[3\cot x + 5c{\text{osec }}x]$
$= 3\frac{d}{{dx}}(\cot x) + 5\frac{d}{{dx}}(cosecx)$
= - 3cosec2x - 5 cosec x cot x

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