Question
Find the derivative of function cosec x cot x.

Answer

Here f (x) = cosec x cot x
$\therefore $f'(x) = $\frac{d}{{dx}}$ [cosec x cot x]
= cosec x $\frac{d}{{dx}}$ (cot x) + cot x $\frac{d}{{dx}}$ (cosec x)
= cosec x . – cosec2 x + cot x . – cosec x cot x
= - cosec3 x – cosec x cot2 x.

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