Question
Find the diagonal of a rectangle whose length is $16\ cm$ and area is $192\ sq.cm.$
✓
Answer
Given,
Length of rectangle, $I =16 cm$
Breadth of rectangle $= b$
Area of rectangle $=$ length $\times$ breadth
$\Rightarrow 192=16 b$
$\Rightarrow b=12 cm$
Also, we know that
Length of diagonal $=\sqrt{ }\left(l^2+b^2\right)$
Where, $I =$ length and $b =$ breadth
$\Rightarrow$ length of diagonal $=\sqrt{ }\left(16^2+12^2\right)$
$=\sqrt{ }(256+144)=20 cm$
Length of rectangle, $I =16 cm$
Breadth of rectangle $= b$
Area of rectangle $=$ length $\times$ breadth
$\Rightarrow 192=16 b$
$\Rightarrow b=12 cm$
Also, we know that
Length of diagonal $=\sqrt{ }\left(l^2+b^2\right)$
Where, $I =$ length and $b =$ breadth
$\Rightarrow$ length of diagonal $=\sqrt{ }\left(16^2+12^2\right)$
$=\sqrt{ }(256+144)=20 cm$
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