MCQ
Find the distance between (12, 3, 4) and (4, 5, 2):
- A$\sqrt{72}$
- B$\sqrt{62}$
- C$\sqrt{64}$
- DNone of these
Solution:
Consider the problem,
Let the given points
A(12, 3, 4) and B(4, 5, 2)
So, distance between A and B by distance formula.
$\text{AB}=\sqrt{(4-12)^2+(5-3)^2+(2-4)^2}=\sqrt{(-8)^2+2^2+(-2)^2}$
$=\sqrt{64+4+4}=\sqrt{72}$
So, distance between the points (12,3,4) and (4,5,2) is $\sqrt{72}\text{ Sq. units.}$
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