Question
Find the equation of an ellipse whose vertices are $(0,\pm10)$ and eccentricity $\text{e}=\frac{4}{5}.$
$\frac{\text{x}^2}{\text{b}^2}+\frac{\text{y}^2}{\text{b}^2}=1\ ,\dots(\text{i})$
The coordinates of vertices are
$(0,\pm\text{b})$ i.e., $(0,\pm10).$$\therefore\ \text{b}=10$
$\Rightarrow\text{b}^2=100$
Now
, $\text{a}^2=\text{b}^2\big(1-\text{e}^2\big)$$\Rightarrow\text{a}^2=100\Big[1-\Big(\frac{4}{5}\Big)^2\Big]$
$\Rightarrow\text{a}^2=100\Big[1-\frac{16}{25}\Big]$
$\Rightarrow\text{a}^2=100\Big[\frac{9}{25}\Big]$
$\Rightarrow\text{a}^2=4\times9=36$
Putting a2 = 36 and b2 = 100 in equation (i), we get$\frac{\text{x}^2}{36}+\frac{\text{y}^2}{100}=1$
$\Rightarrow\frac{100\text{x}^2+36\text{y}^2}{3600}=1$
$\Rightarrow100\text{x}^2+36\text{y}^2=3600$
this is the equation of the required ellipse.Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Vertices
$(\pm6, 0),$ foci $(\pm4, 0)$| | Column C1 | | Column C2 |
| a. | In xy-plane. | i. | Ist octant. |
| b. | Point (2, 3, 4) lies in the. | ii. | yz-plane. |
| c. | Locus of the points having x coordinate 0 is. | iii. | z-coordinate is zero. |
| d. | A line is parallel to x-axis if and only. | iv. | z-axis. |
| e. | If x = 0, y = 0 taken together will represent the. | v. | plane parallel to xy-plane. |
| f. | z = c represent the plane. | vi. | if all the points on the line have equal y and z-coordinates. |
| g. | Planes x = a, y = b represent the line. | vii. | from the point on the respective. |
| h. | Coordinates of a point are the distances from the origin to the feet of perpendiculars. | viii. | parallel to z-axis. |
| i. | A ball is the solid region in the space enclosed by a. | ix | disc. |
| j. | Region in the plane enclosed by a circle is known as a. | x. | sphere. |