Question
Find the equation of the circle with centre $(0, 2)$ and radius $2$

Answer

Here $h = 0, k = 2$ and $r = 2$
The equation of circle is
$(x - h)^2 + (y - k)^2 = r^2$ 
$\therefore (x - 0)^2 + (y - 2)^2 = (2)^2$
$\Rightarrow x^2 + y^2 + 4 - 4y = 4$
$x^2 + y^2 - 4y = 0$
Which is required equation of circle.

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