Gujarat BoardEnglish MediumSTD 11 ScienceMATHSThe Circle1 Mark
Question
Find the equation of the circle with: Centre $(\text{a}\cos\alpha,\ \text{a}\sin\alpha)$ and radius a.
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Answer
The general equation of circle is $(\text{x}-\text{a})^2+(\text{y}-\text{b})^2=\text{r}^2\ .....(\text{A})$ where(a, b)are centre and r is radius From (A) $(\text{x}-\text{a}\cos\alpha)^2+(\text{y}-\text{a}\sin\alpha)^2=\text{a}^2$ $\Rightarrow\text{x}^2-2\text{a}\cos\alpha\text{x}-2\text{a}\sin\alpha\ \text{y}=0$
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