Find the equation of the parabola whose diretrix is x+3=0 - Vidyadip

Question

Find the equation of the parabola whose diretrix is $x+3=0$

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Answer

Here equation of diretrixs is $x+a=0$ that is $x+3=0$ comparing we get $a=3$.
$\therefore$ Equation of the parabola $y^2=4 a x$ that is $y^2=12 x$.

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