Question
Find the greatest number of two digits which is a perfect square.

Answer

We know that $10^2$ is equal to 100 and $9^2$ is equal to 81 . Since 10 and 9 are consecutive numbers, there is no perfect square between 100 and 81 . Since 100 is the first perfect square that has more than two digits, 81 is the greatest two-digit perfect square.

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