Question
Find the inclination of the line whose slope is$: \sqrt{3}$
✓
Answer
If $\tan \theta $ is the slope of a line$;$ then the inclination of the line is $\tan \theta $
Here the slope of line is $\sqrt{3};$ then $\tan \theta = \sqrt{3}$
Now
$\tan \theta = \sqrt{3}$
$\tan \theta = \tan 60^\circ $
$\theta = 60^\circ $
Therefore the inclination of the given line is $\theta = 60^\circ $
Here the slope of line is $\sqrt{3};$ then $\tan \theta = \sqrt{3}$
Now
$\tan \theta = \sqrt{3}$
$\tan \theta = \tan 60^\circ $
$\theta = 60^\circ $
Therefore the inclination of the given line is $\theta = 60^\circ $
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