Question
Find the inclination of the line whose slope is $\sqrt{3}$
✓
Answer
Slope $=\tan \theta$
$ \therefore \sqrt{3}=\tan \theta \ldots ($given$)$
But $\tan 60^{\circ}=\sqrt{3}$
$ \therefore \tan \theta=\tan 60^{\circ}$
$ \therefore \theta=60^{\circ} .$
$ \therefore \sqrt{3}=\tan \theta \ldots ($given$)$
But $\tan 60^{\circ}=\sqrt{3}$
$ \therefore \tan \theta=\tan 60^{\circ}$
$ \therefore \theta=60^{\circ} .$
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