Question
Find the integral: $\int \sec x ( \sec x + \tan x ) d x.$

Answer

Let I = $\int \sec x ( \sec x + \tan x ) d x$
$= \int \left( \sec ^ { 2 } x + \sec x \tan x \right) d x$
$= \int \sec ^ { 2 } x d x + \int \sec x \tan x d x$
= tan x + secx + C

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