Question
Find the $LCM$ and $HCF$ of the following integer by applying the prime factorisation method.
$24, 15$ and $36$

Answer

Let us first find the factors of $24, 15$ and $36.$
$24=2^3 \times 3 $
$15=3 \times 5$
$36=2^2 \times 3^2$
$\text { L.C.M of } 24,15 \text { and } 36=2^3 \times 3^2 \times 5$
$L.C.M$ of $24, 15$ and $36 = 360$
$H.C.F$ of $24, 15$ and $36 = 3$

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