MCQ
Find the least positive integer divisible by 20 and 24.
- A24
- B15
- C12
- ✓120
✓
Answer
Correct option: D.
120
(d): We have, $20=2^2 \times 5 ; 24=2^3 \times 3$
$\therefore \quad$ Required number $=\operatorname{LCM}(20,24)=2^3 \times 3 \times 5=120$
$\therefore \quad$ Required number $=\operatorname{LCM}(20,24)=2^3 \times 3 \times 5=120$
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