Question
Find the length and perimeter of a rectangle, whose area $= 120\ cm^2$ and breadth $= 8\ cm$
✓
Answer
area of rectangle $=120 \ cm ^2$
breadth, $b =8 \ cm$
Area $=I \times b$
$ I \times 8=120$
$ I=\frac{120}{8}=15 \ cm$
Perimeter $=2( l + b )=2(15+8)=2 \times 23=46 \ cm$
Length $=15 \ cm$ ;
Perimeter $=46 \ cm $
breadth, $b =8 \ cm$
Area $=I \times b$
$ I \times 8=120$
$ I=\frac{120}{8}=15 \ cm$
Perimeter $=2( l + b )=2(15+8)=2 \times 23=46 \ cm$
Length $=15 \ cm$ ;
Perimeter $=46 \ cm $
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