Question
Find the magnitude of the vector $\vec{\text{a}}=2\hat{\text{i}}+3\hat{\text{j}}-6\hat{\text{k}}$.

Answer

Given: $\vec{\text{a}}=2\hat{\text{i}}+3\hat{\text{j}}-6\hat{\text{k}}$$\therefore$ Magnitude of the vector $=\big|\vec{\text{a}}\big|=\sqrt{2^2+3^2+(-6)^2}$
$=\sqrt{4+9+36}$
$=\sqrt{49}$
$=7$

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