Question
Find the matrix $X$ of order $2 \times 2$ which satisfies the equation $\left[\begin{array}{ll}3 & 7 \\ 2 & 4\end{array}\right]\left[\begin{array}{ll}0 & 2 \\ 5 & 3\end{array}\right]+2 X =\left[\begin{array}{cc}1 & -5 \\ -4 & 6\end{array}\right]$

Answer

$\begin{aligned} & \text { Given } \\ & {\left[\begin{array}{ll}3 & 7 \\ 2 & 4\end{array}\right]\left[\begin{array}{ll}0 & 2 \\ 5 & 3\end{array}\right]+2 X =\left[\begin{array}{cc}1 & -5 \\ -4 & 6\end{array}\right]} \\ & \Rightarrow\left[\begin{array}{ll}0+35 & 6+21 \\ 0+20 & 4+12\end{array}\right]+2 X =\left[\begin{array}{cc}1 & -5 \\ -4 & 6\end{array}\right] \\ & \Rightarrow\left[\begin{array}{ll}35 & 27 \\ 20 & 16\end{array}\right]+2 X =\left[\begin{array}{cc}1 & -5 \\ -4 & 6\end{array}\right] \\ & 2 X =-\left[\begin{array}{ll}35 & 27 \\ 20 & 16\end{array}\right]+\left[\begin{array}{cc}1 & -5 \\ -4 & 6\end{array}\right] \\ & =\left[\begin{array}{ll}-34 & -32 \\ -24 & -10\end{array}\right] \\ & X =\frac{1}{2}\left[\begin{array}{ll}-34 & -32 \\ -24 & -10\end{array}\right] \\ & =\left[\begin{array}{cc}-17 & -16 \\ -12 & -5\end{array}\right] .\end{aligned}$

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