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Application of Derivatives — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSApplication of Derivatives2 Marks
Question
Find the maximum and minimum value, $g(x) = x^3 + 1$
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Answer

It is given that $g(x) = x^3 + 1$
Now,
$x \in R$
$\Rightarrow-\infty \leq x \leq \infty$
$\Rightarrow-\infty \leq x^{3} \leq \infty$
$\Rightarrow-\infty \leq x^{3}+1 \leq \infty$
The function $g$ neither has a maximum value nor a minimum value.

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