Question
Find the polar co-ordinates of points whose Cartesian co-ordinates are : $(1, \sqrt{3})$

Answer

$(x, y)=(1, \sqrt{3})$
$ \therefore r=\sqrt{x^2+y^2}=\sqrt{1+3}=\sqrt{4}=2$
$\tan \theta=\frac{y}{x}=\frac{\sqrt{3}}{1}=\sqrt{3}$
Since the given point lies in the 1st quadrant,
$\theta=60^{\circ} \ldots\left[\because \tan 60^{\circ}=\sqrt{3}\right]$
$\therefore$ the required polar co-ordinates are $\left(2,60^{\circ}\right)$.

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