Find the probability that a leap year selected at random will con… - Vidyadip

Question

Find the probability that a leap year selected at random will contain $53$ Sundays.

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Answer

There are $366$ days in a leap year.
Total number of outcomes $= 366$
Since in a leap year there are $52$ weeks,
There will surely be $52$ Sundays.
Now, $52 × 7 = 364$ days
So, the last two days could be any of the following outcomes:
$\{($Saturday, Sunday$), ($Sunday, Monday$)\}$
Thus, $P($that there are $53$ Sundays$)$
$=\frac{2}{7}$

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