Question
Find the product.
$\left(\frac{2}{3} x y\right) \times\left(\frac{-9}{10} x^2 y^2\right)$
$\left(\frac{2}{3} x y\right) \times\left(\frac{-9}{10} x^2 y^2\right)$
✓
Answer
We have, $\left(\frac{2}{3} x y\right) \times\left(\frac{-9}{10} x^2 y^2\right)$
$=\left[\frac{2}{3} \times\left(-\frac{9}{10}\right)\right] \times\left(x \times x^2\right) \times\left(y \times y^2\right) $
$ =-\left(\frac{2}{3} \times \frac{9}{10}\right) \times\left(x^3\right) \times\left(y^3\right) $
$ =-\frac{3}{5} x^3 y^3$
$=\left[\frac{2}{3} \times\left(-\frac{9}{10}\right)\right] \times\left(x \times x^2\right) \times\left(y \times y^2\right) $
$ =-\left(\frac{2}{3} \times \frac{9}{10}\right) \times\left(x^3\right) \times\left(y^3\right) $
$ =-\frac{3}{5} x^3 y^3$
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