Question
Find the quotient when difference of $985$ and $958$ is divided by $9.$
✓
Answer
The numbers of three digits are $985$ and $958$ in which tens and ones digits are reversed,
then. $\overline{\text{abc}}-\overline{\text{acb}}=9(\text{b}-\text{c})$
$985 - 958 = 9(8 - 5) = 9 \times 3$
i. e., it is divisible by $9$,
then quotient $= b - c = 8 - 5 = 3$
then. $\overline{\text{abc}}-\overline{\text{acb}}=9(\text{b}-\text{c})$
$985 - 958 = 9(8 - 5) = 9 \times 3$
i. e., it is divisible by $9$,
then quotient $= b - c = 8 - 5 = 3$
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