Question
Find the radius of a sphere whose surface area is 154cm2
✓
Answer
In the given problem, we have to find the radius of a sphere whose surface area is given.
Surface area of the sphere (S) = 154cm2
Let the radius of the sphere be rcm
Now, we know that surface area of the sphere $=4\pi\text {r}^2$
So,
$154=4\Big(\frac{22}{7}\Big)(\text{r})^2$
$\text{r}^2=\frac{(154)(7)}{(4)(22)}$
$\text{r}^2=12.25$
Further, solving for r
$\text{r}=\sqrt{12.25}$
$\text{r}=3.5$
Therefore, the radius of the given sphere is 3.5cm.
Surface area of the sphere (S) = 154cm2
Let the radius of the sphere be rcm
Now, we know that surface area of the sphere $=4\pi\text {r}^2$
So,
$154=4\Big(\frac{22}{7}\Big)(\text{r})^2$
$\text{r}^2=\frac{(154)(7)}{(4)(22)}$
$\text{r}^2=12.25$
Further, solving for r
$\text{r}=\sqrt{12.25}$
$\text{r}=3.5$
Therefore, the radius of the given sphere is 3.5cm.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write in decimal form and state what kind of decimal expansion: $\frac{3}{{13}}$
→Assuming that x, y, z are positive real numbers, simplify the following:
$\Big(\frac{\text{x}^{-4}}{\text{y}^{-10}}\Big)^{\frac{5}{4}}$
→$\Big(\frac{\text{x}^{-4}}{\text{y}^{-10}}\Big)^{\frac{5}{4}}$
In the given figure, the side BC of $\triangle\text{ABC}$ has been produced on both sides-on the left to D and on the right to E. If $\angle\text{ABD}=106^\circ$ and $\angle\text{ACE}=118^\circ,$ find the measure of each angle of the triangle.
→Factorise:
x6 - 7x3 - 8
x6 - 7x3 - 8
The mean weight of 6 boys in a group is 48kg The individual weights of five of them are 51kg, 45kg, 49kg, 46kg and 44kg. Find the weight of the sixth boy.
Factorize:
a2 + b2 + 2(ab + bc + ca)
a2 + b2 + 2(ab + bc + ca)
Factorise:
Evaluate {(999)2 - 1}
Find the measure of an angle which is 36º more than its complement.
In the adjoining figure, ABC and ABD are two triangles on the same base AB. If line segment CD is
bisected by AB at O, show that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{ABD}).$
→bisected by AB at O, show that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{ABD}).$