Question
Find the second-order derivative of the function log x

Answer

Let y = log x
Now,
$\frac{d y}{d x}=\frac{d}{d x}(\log x)=\frac{1}{x}$
Therefore,
$\frac{d^{2} y}{d x^{2}}=\frac{d}{d x}\left(\frac{1}{x}\right)=\left(-\frac{1}{x^{2}}\right)$

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