Question
Find the square of : $3a - 4b$
✓
Answer
We know that
$( a - b )^2 = a^2 + b^2 - 2ab$
$( 3a - 4b )^2 = 9a^2 + 16b^2 - 2 \times 3a \times 4b$
$= 9a^2 + 16b^2 - 24ab$
$( a - b )^2 = a^2 + b^2 - 2ab$
$( 3a - 4b )^2 = 9a^2 + 16b^2 - 2 \times 3a \times 4b$
$= 9a^2 + 16b^2 - 24ab$
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