Question
Find the square of $a+\frac{1}{5 a}$
✓
Answer
$ \left(\mathrm{a}+\frac{1}{5 \mathrm{a}}\right)^2$
$=(\mathrm{a})^2+\left(\frac{1}{5 \mathrm{a}}\right)^2+2 \times \mathrm{a} \times \frac{1}{5 \mathrm{a}}$
$ =\mathrm{a}^2+\frac{1}{25 \mathrm{a}^2}+\frac{2}{5}$
$=(\mathrm{a})^2+\left(\frac{1}{5 \mathrm{a}}\right)^2+2 \times \mathrm{a} \times \frac{1}{5 \mathrm{a}}$
$ =\mathrm{a}^2+\frac{1}{25 \mathrm{a}^2}+\frac{2}{5}$
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